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Progression

    2 nd iteration
    Step1:
      s11 = on(B, Table) ^ on(C, Table) ^ on(D, C) ^ clear(B) ^ clear(D) ^ holding(A)
    Step 2:
      Applicable actions: putdown (A) , stack(A,D)
    Step 3:
      s111 = result(s11, ‹putdown (A)›) = on(B, Table) ^ on(C, Table) ^ on(D, C) ^ clear(B) ^ clear(D) ^ holding(A) on(x, Table) ^ handEmpty ^ clear(x) \ holding(x) = on(A, Table) ^ on(B, Table) ^ on(C, Table) ^ on(D, C) ^ clear(A) ^ clear(B) ^ clear(D) ^ handEmpty
      we are back in the initial state!

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