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Progression
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4
th
iteration
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Step1:
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s12 = on(A, Table) on(C, Table) on(D, C) ^ clear(A) ^ clear(D) ^ holding(B)
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Step 2:
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Applicable actions: putdown (B), stack(B,D)
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Step 3:
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s121 = result(s12, 〈putdown (B)〉) = on(A, Table) on(C, Table) on
(D, C) ^ clear(A) ^ clear(D) ^ holding(B) ∪ on(x, Table) ^
handEmpty ^ clear(x) \ holding(x) = on(A, Table) on(B, Table) on
(C, Table) on(D, C) ^ clear(A) ^ clear(B) ^ clear(D) ^ handEmpty
we are back in the initial state!
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