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    4 th iteration
      s12 = on(A, Table) on(C, Table) on(D, C) ^ clear(A) ^ clear(D) ^ holding(B)
    Step 2:
      Applicable actions: putdown (B), stack(B,D)
    Step 3:
      s121 = result(s12, 〈putdown (B)〉) = on(A, Table) on(C, Table) on (D, C) ^ clear(A) ^ clear(D) ^ holding(B) ∪ on(x, Table) ^ handEmpty ^ clear(x) \ holding(x) = on(A, Table) on(B, Table) on (C, Table) on(D, C) ^ clear(A) ^ clear(B) ^ clear(D) ^ handEmpty

      we are back in the initial state!

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